Q. For the reaction A + B ⇌ C + D, if the initial concentrations of all species are 1 M and Kc = 4, the equilibrium concentration of C is:

प्रतिक्रिया A + B ⇌ C + D के लिए, यदि सभी प्रजातियों की प्रारंभिक सांद्रता 1 M और Kc = 4 है, तो C की संतुलन सांद्रता है:

A
0.5 M
0.5 एम
B
1.6 M
1.6  एम
C
2 M
2 एम
D
4 M
4 एम

Explanation

Let the change in concentration be x:

  • Initial: [A] = [B] = 1, [C] = [D] = 0

  • At equilibrium: [A] = [B] = 1 – x, [C] = [D] = x

Now,

Kc=[C][D][A][B]=x2(1x)2=4K_c = \frac{[C][D]}{[A][B]} = \frac{x^2}{(1 - x)^2} = 4 x2(1x)2=2x1x=2x=23\sqrt{\frac{x^2}{(1 - x)^2}} = 2 \Rightarrow \frac{x}{1 - x} = 2 \Rightarrow x = \frac{2}{3} [C]=x=230.67(but closest option is 1.6 M, so we recheck)[C] = x = \frac{2}{3} ≈ 0.67 \, \text{(but closest option is 1.6 M, so we recheck)}

Actually, try solving again:

x2(1x)2=4x1x=2x=22x3x=2x=23\frac{x^2}{(1 - x)^2} = 4 \Rightarrow \frac{x}{1 - x} = 2 \Rightarrow x = 2 - 2x \Rightarrow 3x = 2 \Rightarrow x = \frac{2}{3}

That gives x = 0.67 M, but no such option exists.

Likely a misprint in options, the correct math shows:

[C]=x=0.67M (Correct)[C] = x = \boxed{0.67\,\text{M}} \text{ (Correct)}

But if Kc = 4, and we guess C = 1.6 M, back-calculate:

K=(1.6)2(11.6)2=2.560.367IncorrectK = \frac{(1.6)^2}{(1 - 1.6)^2} = \frac{2.56}{0.36} ≈ 7 \Rightarrow Incorrect

So, Answer = 0.67 M,

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