Q. The solubility product (Ksp) of AgCl is 1.8 × 10⁻¹⁰. The solubility of AgCl in mol L⁻¹ is:

AgCl का घुलनशीलता उत्पाद (Ksp) 1.8 × 10⁻¹⁰ है। AgCl की mol L⁻¹ में घुलनशीलता है:

A
1.8 × 10⁻¹⁰
B
1.34 × 10⁻⁵
C
3.6 × 10⁻¹⁰
D
9.0 × 10⁻¹¹

Explanation

For:

AgCl (s)Ag⁺+Cl⁻\text{AgCl (s)} ⇌ \text{Ag⁺} + \text{Cl⁻}

Let solubility = s, so:

Ksp=[Ag+][Cl]=s2s=Ksp=1.8×10101.34×105 mol/LK_{sp} = [Ag⁺][Cl⁻] = s² \Rightarrow s = \sqrt{K_{sp}} = \sqrt{1.8 × 10^{-10}} ≈ 1.34 × 10^{-5} \text{ mol/L}

Invest in Future Achievers

Your support helps keep Exam Achiever 100% free for students preparing for exams.

Thanks for your support!

Comments

Leave a Comment