Q. In the reaction: 2NO + O₂ → 2NO₂, if the rate of disappearance of O₂ is 0.6 mol·L⁻¹·s⁻¹, the rate of formation of NO₂ is:

प्रतिक्रिया में: 2NO + O₂ → 2NO₂, यदि O₂ के लुप्त होने की दर 0.6 mol·L⁻¹·s⁻¹ है, तो NO₂ के बनने की दर है:

0.3 mol·L⁻¹·s⁻¹

0.6 mol·L⁻¹·s⁻¹

1.2 mol·L⁻¹·s⁻¹

2.4 mol·L⁻¹·s⁻¹

Given:

\text{Rate of disappearance of } O_2 = 0.6

From stoichiometry:

2NO + O_2 \to 2NO_2

The rate of disappearance of O₂ is related to the rate of formation of NO₂ by the mole ratio:

Rate of N O_{2} = 2 \times Rate of O_{2} = 2 \times 0.6 = 1.2

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