Q. The slope of the straight line obtained by plotting ln k vs 1/T gives:

ln k बनाम 1/T आलेखित करके प्राप्त सीधी रेखा का ढलान देता है:

Activation energy
सक्रियण ऊर्जा

Frequency factor
आवृत्ति कारक

Rate constant
दर स्थिर

Collision frequency
टकराव की आवृत्ति

From Arrhenius equation:

\ln k = \ln A - \frac{E_a}{R} \cdot \frac{1}{T}

Plot of $\ln k$ vs $1/T$ has slope $- E_{a} / R$

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