Q. The time required for 99.9% completion of a first-order reaction is equal to:

प्रथम-क्रम प्रतिक्रिया के 99.9% पूरा होने के लिए आवश्यक समय बराबर है:

A
t₁/₂
B
3t₁/₂
C
6.9t₁/₂
D
10t₁/₂

Explanation

Fraction remaining = 0.1% = 0.001
For first order:

ln[A]0[A]=kt\ln \frac{[A]_0}{[A]} = ktln10.001=kt=6.9\ln \frac{1}{0.001} = kt = 6.9

Since

t1/2=0.693kk=0.693t1/2t_{1/2} = \frac{0.693}{k} \Rightarrow k = \frac{0.693}{t_{1/2}} t=6.9k=6.9×t1/2t = \frac{6.9}{k} = 6.9 \times t_{1/2}

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