Q. The freezing point of a 0.1 m aqueous solution of NaCl would be: (Kf for water = 1.86°C/m)

NaCl के 0.1 m जलीय घोल का हिमांक बिंदु होगा: (पानी के लिए Kf = 1.86°C/m)

A
-0.186°C
B
-0.372°C
C
0.186°C
D
0.372°C

Explanation

NaCl dissociates into 2 ions, so i=2.

Freezing point depression:

ΔTf=i×Kf×m=2×1.86×0.1=0.372C

Freezing point = 0 - 0.372 = -0.372°C.

Invest in Future Achievers

Your support helps keep Exam Achiever 100% free for students preparing for exams.

Thanks for your support!

Comments

Leave a Comment