Q. A body of mass 2 kg is moving with a speed of 5 m/s. A constant force stops it in 4 m. What is the magnitude of the force applied?

2 किलोग्राम द्रव्यमान का एक पिंड 5 मीटर/सेकेंड की गति से चल रहा है। एक स्थिर बल इसे 4 मीटर में रोक देता है। लगाए गए बल का परिमाण क्या है?

5 N

6.25 N

10 N

12.5 N

Using work-energy principle: Work done by the force = change in kinetic energy

$W = F \times d = \Delta KE = \frac{1}{2} m v^2 - 0$

Force acts opposite to motion, so work done = $-F \times d$

$F \times d = \frac{1}{2} m v^2$

Calculate force magnitude:

$F = \frac{\frac{1}{2} m v^2}{d} = \frac{\frac{1}{2} \times 2 \times 5^2}{4} = \frac{25}{4} = 6.25 \text{ N}$

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