Q. The dimension of coefficient of viscosity is:

श्यानता के गुणांक का आयाम है:

M¹L⁻¹T⁻¹

M⁻¹L¹T⁻¹

M⁻¹L¹T¹

M⁻¹L⁻¹T¹

Viscosity $\eta$ appears in Newton’s law of viscosity:

\tau = \eta \frac{du}{dy}

Where:

So, viscosity dimension = $\frac{\text{Shear stress}}{\text{Velocity gradient}} = M L^{-1} T^{-1}$

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