Q. The moment of inertia of a solid cylinder about its central axis is given by which formula?

किसी ठोस बेलन का उसके केंद्रीय अक्ष के परितः जड़त्व आघूर्ण किस सूत्र द्वारा दिया जाता है?

A
(1/2)MR²
(1/2)एमआर²
B
MR²
एमआर²
C
(1/4)MR²
(1/4)एमआर²
D
(2/5)MR²
(2/5)एमआर²

Explanation

For a solid cylinder of mass MM and radius RR rotating about its central axis, the moment of inertia is:

I=12MR2I = \frac{1}{2}MR^2

This quantifies how mass is distributed relative to the axis of rotation, affecting the object's resistance to angular acceleration.

Invest in Future Achievers

Your support helps keep Exam Achiever 100% free for students preparing for exams.

Thanks for your support!

Comments

Leave a Comment