Q. For a mass-spring system undergoing SHM, doubling the mass will:

एसएचएम से गुजरने वाली मास-स्प्रिंग प्रणाली के लिए, द्रव्यमान को दोगुना करने से:

Double the time period
समयावधि को दोगुना करें

Halve the time period
समयावधि आधी कर दें

Increase the time period by a factor of √2
समयावधि को √2 के कारक से बढ़ाएँ

Decrease the time period by a factor of √2
समयावधि को √2 के कारक से कम करें

The time period $T$ of a mass-spring system is:

T = 2\pi \sqrt{\frac{m}{k}}

If mass $m$ is doubled:

T' = 2\pi \sqrt{\frac{2m}{k}} = T \cdot \sqrt{2}

So, the time period increases by a factor of √2.

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