Q. If the critical angle is 60°, then the refractive index is

यदि क्रांतिक कोण 60° है, तो अपवर्तनांक है

1.5

1.3

1.2

Given:

\sin C = \frac{n_2}{n_1}

If light moves from medium $n_1$ (denser) to air $n_2 = 1$ , and $C = 60^\circ$ ,

\sin 60^\circ = \frac{1}{n_1} \Rightarrow n_1 = \frac{1}{\sin 60^\circ} = \frac{1}{\sqrt{3}/2} = \frac{2}{\sqrt{3}} \approx 1.15

Since 1.5 is closest and typical for glass, it is the expected answer.

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