Q. The EMF of the cell Zn|Zn²⁺(0.01M)n²⁺(0.1M)|Zn at 25°C is:

25°C पर सेल Zn|Zn²⁺(0.01M)n²⁺(0.1M)|Zn का ईएमएफ है:

0.0295 V
0.0295 वी

0.059 V
0.059 वी

0.0295 V in reverse direction
विपरीत दिशा में 0.0295 V

Zero
शून्य

This is a concentration cell. EMF is given by:

E = \frac{0.0591}{n} \log\left(\frac{[dilute]}{[concentrated]}\right) = \frac{0.0591}{2} \log\left(\frac{0.01}{0.1}\right) = 0.0295 \log(0.1) = 0.0295 × (–1) = –0.0295 \, \text{V}

So, EMF = 0.0295 V in reverse direction

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