Q. The number of faradays required to deposit 3 moles of aluminum from Al³⁺ solution is:

Al³⁺ विलयन से 3 मोल एल्यूमीनियम जमा करने के लिए आवश्यक फैराडे की संख्या है:

A

3

B

6

C

9

D

12

Explanation

For Al³⁺:

\text{1 mole of Al requires 3 faradays (since it’s a 3+ ion)}

So, for 3 moles:

3 \times 3 = 9 faradays

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