Q. If the temperature of a gas is doubled and the pressure is halved, the volume will:
यदि किसी गैस का तापमान दोगुना कर दिया जाए और दबाव आधा कर दिया जाए, तो आयतन होगा:
Explanation
Given: Temperature doubles (T₂ = 2T₁), Pressure halves (P₂ = P₁/2)
Using combined gas law: P₁V₁/T₁ = P₂V₂/T₂
Solving for V₂: V₂ = (P₁V₁T₂)/(T₁P₂)
Substituting values: V₂ = (P₁ × V₁ × 2T₁)/(T₁ × P₁/2) V₂ = (2P₁V₁T₁)/(T₁P₁/2) V₂ = 2V₁ × 2 = 4V₁
Therefore: Volume quadruples
Physical reasoning:
- Temperature doubling increases volume by factor of 2
- Pressure halving increases volume by factor of 2
- Combined effect: 2 × 2 = 4 times increase
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