Q. How many moles of KMnO₄ are required to react with 0.1 mole of FeSO₄ in acidic medium according to the equation: 5FeSO₄ + 2KMnO₄ + 8H₂SO₄ → 5Fe₂(SO₄)₃ + K₂SO₄ + 2MnSO₄ + 8H₂O?

समीकरण के अनुसार अम्लीय माध्यम में 0.1 मोल FeSO₄ के साथ प्रतिक्रिया करने के लिए KMnO₄ के कितने मोल की आवश्यकता होती है: 5FeSO₄ + 2KMnO₄ + 8H₂SO₄ → 5Fe₂(SO₄)₃ + K₂SO₄ + 2MnSO₄ + 8H₂O?

0.02 mol
0.02 मोल

0.04 mol
0.04 मोल

0.1 mol
0.1 मोल

0.5 mol
0.5 मोल

Given reaction: 5FeSO₄ + 2KMnO₄ + 8H₂SO₄ → 5Fe₂(SO₄)₃ + K₂SO₄ + 2MnSO₄ + 8H₂O

Wait, let me check this equation - it appears unbalanced. Let me work with the given stoichiometry:

From the equation: 5 mol FeSO₄ react with 2 mol KMnO₄ Given: 0.1 mol FeSO₄

Using stoichiometry:

5 mol FeSO₄ : 2 mol KMnO₄
0.1 mol FeSO₄ : x mol KMnO₄

x = (0.1 × 2) ÷ 5 = 0.04 mol KMnO₄

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