Q. The molarity of a solution containing 4.9 g of H₂SO₄ in 250 mL of solution is:
250 एमएल घोल में 4.9 ग्राम H₂SO₄ वाले घोल की मोलरता है:
Explanation
Given:
- Mass of H₂SO₄ = 4.9 g
- Volume of solution = 250 mL = 0.25 L
- Molar mass of H₂SO₄ = 2(1) + 32 + 4(16) = 98 g/mol
Steps:
- Moles of H₂SO₄ = 4.9 g ÷ 98 g/mol = 0.05 mol
- Molarity = moles/volume = 0.05 mol ÷ 0.25 L = 0.2 M
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