Q. In a mass-spring system, if the spring constant is quadrupled, the time period will:

द्रव्यमान-स्प्रिंग प्रणाली में, यदि स्प्रिंग स्थिरांक को चौगुना कर दिया जाए, तो समय अवधि होगी:

A
Double
दोहरा
B
Halve
आधा करना
C
Remain the same
एक ही रहेगा
D
Decrease by a factor of 2√2
2√2 के कारक से कमी

Explanation

Time period T=2πmkT = 2\pi \sqrt{\frac{m}{k}}

If kk becomes 4k4k, then:

T=2πm4k=122πmk=T2T = 2\pi \sqrt{\frac{m}{4k}} = \frac{1}{2} \cdot 2\pi \sqrt{\frac{m}{k}} = \frac{T}{2}

Invest in Future Achievers

Your support helps keep Exam Achiever 100% free for students preparing for exams.

Thanks for your support!

Comments

Leave a Comment