Q. The molecular mass of Ca₃(PO₄)₂ is approximately: (Ca=40, P=31, O=16)

Ca₃(PO₄)₂ का आणविक द्रव्यमान लगभग है: (Ca=40, P=31, O=16)

A
310 amu
310 एमू
B
142 amu
142 एमू
C
278 amu
278 एमू
D
310 g/mol
310 ग्राम/मोल

Explanation

Given atomic masses: Ca = 40, P = 31, O = 16

Calculation:

3 Ca atoms: 3 × 40 = 120

2 P atoms: 2 × 31 = 62

8 O atoms: 8 × 16 = 128

Total molecular mass = 120 + 62 + 128 = 310 amu

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